Physics, asked by BMBSHANKAR, 5 months ago

figure shows 2 blocks A and B connected to an ideal Pulley string system. in this system when bodies are released then

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Answers

Answered by Janulingu
4

Answer:

6 m/s²____a

16N_____T

32N____F

Answered by soniatiwari214
0

Your question was incomplete. Please check below the full content.

the figure shows 2 blocks A and B connected to an ideal Pulley string system. in this system when bodies are released then

a) Acceleration of block A is 1m/s^2

b) Acceleration of block A is 2m/s^2

c) Tension in the string connected to block B is 40 N

d) Tension in the string connected to block B is 80 N

Concept:

  • Pulley systems
  • Tension and acceleration

Given:

  • Mass of block A Ma = 40kg
  • Mass of block B Mb = 10 kg
  • Let acceleration of block A = a
  • Tension on string connecting B = T

Find:

  • The acceleration of block A or
  • The tension in the string connected to block B

Solution:

Tension on string connecting B = T

So, the tension in the string connecting A = 4T

When block B moves a distance of d, block A will move a distance of d/4

acceleration of block A = a

Acceleration of block B= 4a

Block A will move downwards

Ma g -4T = Ma a

40g - 4T = 40a

10g - T = 10a

Block B will move toward the left due to the tension in the string

T = Mb 4a

T = 40 a

10g - T = 10a

10g -40a = 10a

10g = 50 a

100 = 50a

a = 100/50 = 2 m/s^2

The correct option is B.

#SPJ3

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