Figure shows a three block system of masses m,
2m and 3m. The net contact force on 2m mass is
m
2m
3m
(1 mg
(2) 2mg
(3) 3mg
(4) Zero
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TRICK : here the whole system is moving with constant speed which means that he net force between an of them is 0
Taking the middle part only
Net force = T1 - T2 - 2mg
As the body is moving u , net force on that body provide motion
Therefore T1 - T2 - 2mg = 0
OR
consider the whole block
F - 6 mg = 0 -------- F = 6 mg
consider the first block
F - T1 - mg = m0 = 0 --------------- T1 = 5mg
for the last block
T2 - 3 mg = 0----------------------- T2 = 3mg
For the second block
T1 - T2 - 2mg = 5mg - 3mg - 2mg = 0
Hope you understand
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