Question

Figure shows a uniform disc, with mass M-2.4 kg and radus
on mounted on a fixed horizontal axle. A block als
-1.2 kg hangs from a massless cord which is wrapped around
the rim of the disc. The tension in the cord is​

Answer 1

Answer:

Concept:

Newton's laws of motion. There are 3 laws in newtons laws of motion.

Explanation:

$For \ unwrapping \ without \ shipping \Rightarrow \mathrm{R} \alpha=\mathrm{a} In rotatory motion of disc,$

TR = I disc $\alpha$

TR = ${\mathrm{MR}^{2}$ / 2 × $\alpha$

${T}=\frac{\mathrm{Mg}}{2}$ --------(i)

$In translation \ of \ block,\\ \mathrm{mg}-\mathrm{T}=\mathrm{ma}---\text { (ii) }^{-1} From (i) and (ii)$

$\begin{aligned}&\mathrm{mg}-\mathrm{T}=\frac{2}{\mathrm{M}} \mathrm{mT} \\&\mathrm{mg}=\mathrm{T}\left[1+\frac{2 \mathrm{~m}}{\mathrm{M}}\right] \\&\Rightarrow \mathrm{T}=\frac{\mathrm{mg}}{\left[1+\frac{2 \mathrm{~m}}{\mathrm{M}}\right]}=\frac{(1.2) 10}{\left[1+\frac{2 \times 1.2}{2.4}\right]}=6 \mu\end{aligned}$

The tension in the cord is​ 6$\mu$

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