Physics, asked by sheware, 11 months ago

Figure shows elliptical path abcd of a planet around the sun

S such that the area of triangle csa is1/4
the area of the
ellipse. (See figure) With db as the semimajor axis, and ca as
the semiminor axis. Ift, is the time taken for planet to go
over path abc and t, for path taken over cda then:​

Answers

Answered by qyasmeen703
0

Answer:

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Answered by Fatimakincsem
3

The time taken for planet to go  over path abc and t, for path taken over cda is t1 = 3t2

Explanation:

Total area = A

area of SABC = 3A / 4

Area of SADC = A / 4

3A / 4t1 = A / t2

=> t1 = 3t2

Thus the time taken for planet to go  over path abc and t, for path taken over cda is t1 = 3t2 .

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