Figure shows elliptical path abcd of a planet around the sun
S such that the area of triangle csa is1/4
the area of the
ellipse. (See figure) With db as the semimajor axis, and ca as
the semiminor axis. Ift, is the time taken for planet to go
over path abc and t, for path taken over cda then:
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The time taken for planet to go over path abc and t, for path taken over cda is t1 = 3t2
Explanation:
Total area = A
area of SABC = 3A / 4
Area of SADC = A / 4
3A / 4t1 = A / t2
=> t1 = 3t2
Thus the time taken for planet to go over path abc and t, for path taken over cda is t1 = 3t2 .
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