Figure shows the thrust -time graph of a rocket .If the mass of the rocket 1 minute after starting from rest is
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25
answer : option (2) 180m/s
explanation : we know, area enclosed by thrust - time graph = change in linear momentum.
or, area of trapezium as shown in figure = m(v - u)
but rocket starts from rest so, u = 0
or, area of trapezium = mv .......(1)
and area of trapezium = 1/2 × (sum of parallel side) × distance between two parallel side
= 1/2 × (30s + 60s) × 4000N
= 180000 Ns......(2)
given, weight of rocket , m = 1ton = 1000kg
now from equations (1) and (2),
180000 Ns = 1000 × v
v = 180 m/s
hence, velocity of rocket after 1 minute is 180 m/s .
explanation : we know, area enclosed by thrust - time graph = change in linear momentum.
or, area of trapezium as shown in figure = m(v - u)
but rocket starts from rest so, u = 0
or, area of trapezium = mv .......(1)
and area of trapezium = 1/2 × (sum of parallel side) × distance between two parallel side
= 1/2 × (30s + 60s) × 4000N
= 180000 Ns......(2)
given, weight of rocket , m = 1ton = 1000kg
now from equations (1) and (2),
180000 Ns = 1000 × v
v = 180 m/s
hence, velocity of rocket after 1 minute is 180 m/s .
Answered by
4
Answer:
anewer is 180m/s
Explanation:
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