Question

Figure shows three electric field lines. If and are the forces on a test charge at the positions A, B, and C respectively, then

Answer 1

Answer:

The line joining B to C is perpendicular to electric field, so potential of B = potential of C i.e., VB = VC. Distance AB = 4cm Potential difference between A and C = E x (AB) = 5 x 103 x (4 x 10-2) = 200volt