Question

From a point on a level ground the angle of elevation to the top of the tower is 60'. If the tower is 346m high, what is the distance of the point from the foot of the tower? (V3 1.73)​

Answer 1

Step-by-step explanation:

Let AB be the tower.

Then, ∠APB=30

∘

and AB=100 m.

AP

AB

=tan30

∘

=

3

1

⇒AP=(AB×

3

)m

=100

3

m

=(100×1.73)m

=173 m.