Question

Figure shows two processes A and B on a system. Let ∆Q1 and ∆Q2 be the heat given to the system in processes A and B respectively. Then
(a) ∆Q1 > ∆Q2 (b) ∆Q1 = ∆Q2 (c) ∆Q1 < ∆Q2 (d) ∆Q1 ≤ ∆Q2.
Figure

Answer 1

Answer:

( b) Δ1=Δ2.............

Answer 2

Answer is Option (a)

Explanation:

$\Delta U = \Delta Q_a_b_s - W_{by gas}$

As internal energy depends only on initial and final state.  

So, $\Delta U_1 = \Delta U_2$

$\Delta \theta _{absorbed} = [\Delta Q_a_b_s - W_{by gas}]$

So,  

$W_{by gas}$= area under P-V Diagram

Hence, $W_{by gas}$ for path a is greater and $\Delta U$ is same  

So,  

$\Delta \theta _{a} > \Delta \theta _{b}$

* Refer P-V Diagram