Question

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Answer 1

Answer:

900 cm^2 is the highest area of the rectangle having perimeter 60cm.

Step-by-step explanation:

let length=l and breadth=b

the perimeter of rectangle is

p = l + b = 60cm

as told in question we have to find maximum area of rectangle so ,

Area ,A=l×b

here, A is directly proportional to l and b so for maximum we have to take same in this condition...

so l=b then A = l×l = l^2

now, p=l+l

60 = 2l

l=60/2

l=30cm

Area , A = l×l

= 30 × 30

A = 900cm^2

This is the maximum area....