Math, asked by kummirekha0, 1 month ago



fill in the blank of 1st and 2nd factor ​

Attachments:

Answers

Answered by pradiptadas2007
2

Answer:

Polynomial 1st factor 2nd factor

2x+4 x+2 2

8-28y+12y² 4 2-7y+3y²

(x+2)³-3(x+2) x+2 x²+4x+1

2ab-5a³b+b³ a³b 2ab³-5+b²

Hope it helps you...

Pls mrk me brainliest...

Answered by bagkakali
1

Answer:

polynomial 2x+4=2(x+2)

1st factor 2

2nd factor (x+2)

1st factor 4

2nd factor 2-7y+3y^2

polynomial 4(2-7y+3y^2)=8-28y+12y^2

polynomial (x+2)^3-3(x+2)

=(x+2){(x+2)^2-3}

=(x+2)(x^2+4x+4-3)

=(x+2)(x^2+4x+1)

1st factor (x+2)

2nd factor (x^2+4x+1)

1st factor a^3b

2nd factor 2ab^3-5+b^2

polynomial a^3b(2ab^3-5+b^2)

=2a^4b^4-5a^3b+a^3b^3

Similar questions