Fill in the blanks
1) (2x-3y)³= ?
2)(2x+y-z)² = ?
3)(3a+b)³ = ?
madhura41:
Hii
Your answer here....
(2x-3y)^3 = >>> (2x)^3-3 x (2x)^2 x 3y+3 x 2x x (3y)^2-(3y)^3.............8x^3-3 x (2x)^2 x 3y + 3x 2x x (3y)^2-(3y)^3.............8x^3-3x(4x)^2 x 3y+3 x (2x) x 9y^2- 27y^3............8x^3-36x^2y+54xy^2- 27y^3
(2x+y-z)^2. = 4x^2+y^2+(-z)^2+4xy- 4xz- 2yz...........= 4x^2+y^2+z^2+ 4xy- 4xz
(3a+b)^3 = ..(3a)^3+3 x (3a)^2 x b+3 x 3ab^2+b^3...........=27a^3+3 x 9a^2b+9ab^2+b^3...........=27a^3+27a^2b+9ab^2+b^3
I think its help U Formula :: (a+b)2 = a2+2ab + b2; a2 + b2 = (a+b)2-ab..
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x = 1+√2 + √3; then find 2x4 – 8x3 – 5x2 + 26x – 28. A) 6 √6 ... Now (x + 1/x) ² = 3 (given) => x + 1/x .... x³ – 8 – 6x(x – 2) = ( 21/3)³ + (22/3)³ + 3(21/3 x 22/3)(21 ...
Thank you
but i didn't understand it
ok .......i explain but in 6:00 pm
ok
u got u r ans..????naa!!
(2x-3y)^3 = (2x^3-3 x (2x)^2 x 3y+ 3 x 2x x (3y)^2-(3y)^3.............=8x^3-3 x (2x)^2 x 3y+ 3x 2x x (3y)^2-(3y)^3.............= 8x^3-3x(4x)^2 x 3y+ 3 x (2x) x 9y^2-27y^3............= 8x^3-36x^2y+54xy^2-27^3.................................(2) (2x+y-z)^2 = ..4x^2+y^2+(-z)^2+4xy-4xz- 2yz...........= 4x^2+y^2+z^2+4xy- 4xz..................................(3) ..(3a+b)^3 = ..(3a)^3+3 x (3a)^2 x b+3 x 3ab^2+b^3......................= 27 a^3+3 x 9a^2b+9ab^2+b^3................=27a^3+27a^2b+9ab^2+b^3.
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