Question

Fill in the blanks : (c) Principal = Rs.1280, Time = (2 whole 1/2 years), Rate of Interest = (2 whole 3/4)% Simple Interest = ___, Amount = ___.

Answer 1

Fill in the blanks : (c) Principal = Rs.1280, Time = (2 whole 1/2 years), Rate of Interest = (2 whole 3/4)% Simple Interest = ___, Amount = ___.

SOLUTION :-

Principal (P) = Rs 1280

Rate of Interest (R) = 2 whole $\frac{3}{4}$ % per annum = 2.75 % p.a

Time (T) = 2 whole $\frac{1}{2}$ Years = 2.5 years

To be found :-

The Simple Interest (S.I)

and Amount (A)

S.I = $\frac{P \times R \times T }{100}$

S.I = $\frac{1280 \times 2.75 \times 2.5}{100}$

S.I = Rs 88

Now,

Amount (A) = Principal (P) + Simple Interest (S.I)

Amount (A) = Rs 1280 + Rs 88

Amount (A) = Rs 1368

Hence

The Simple Interest (S.I) = Rs 88

and

Amount (A) = Rs 1368

Answer 2

▶ Question :-

→ Fill in the blanks : (c) Principal = Rs.1280, Time = (2 whole 1/2 years), Rate of Interest = (2 whole 3/4)% Simple Interest = ___, Amount = ___.

▶ Answer :-

→ SI = 88.

→ Amount = ₹1368.

▶ Explanation :-

▶ Given :-

→ Principal (p) = ₹1280 .

→ Time (t) = $2 \frac{1}{2}$ years = 2.5 years .

→ Rate (R) = $2 \frac{3}{4}$ % = 2.75 % .

▶ To find :-

→ Simple Interest (SI) .

→ Amount .

▶ Solution :-

$\sf \therefore SI = \frac{p \times r \times t}{100} . \\ \\ \sf = \frac{1280 \times 2.5 \times 2.75}{100} . \\ \\ \sf = \frac{88 \cancel{00}}{ \cancel{100}} . \\ \\ \large \boxed{ \red{ \sf \therefore SI = 88.}}$

And, we know that :-

°•° Amount = SI + principal .

= 88 + 1280.

$\large \boxed{ \red { \sf \therefore Amount = 1368. }}$

✔✔ Hence, it is solved ✅✅.