for what values of b is (x-5) of factor of x^3-2x^2 +bx-12
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put x=5 and then equate the equation as equal to zero... then find out the value of b
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x^3-2x^2+bx-12
(x-5)
x=5
5^3-2(5)^2+b(5)-12=0
125-50+5b-12=0
53+5b=0
5b=-53
b=-53/5
hope it helps!!!!!!
(x-5)
x=5
5^3-2(5)^2+b(5)-12=0
125-50+5b-12=0
53+5b=0
5b=-53
b=-53/5
hope it helps!!!!!!
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