Math, asked by archi9493, 1 year ago

fill in the blanks (i) p(E)+________=1 (ii) we get ______ results on throwing a dice. (iii) p*E)=___________________/total number of possible outcomes.​


Anonymous: ___k off
ajaz2676: what happen brother

Answers

Answered by harsha1491
3
(i) p(E)+ P(Not E) =1
(ii) we get 6 results on throwing a dice.
(iii) p*E)= 1 - P(E) /total number of possible outcomes.​
Answered by ajaz2676
1

p(not sure event)= 1.2 we get 6 out comes.3= total number of favourable outcome

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