Fill in the blanks with a numbers
1,2, 3,4, 5, 6, 7, 8, 9,without repetition
_ _x_=_ _+_ _=_ _
Answers
Answer:
1 7 x 4 = 6 8 + 2 5 = 9 3
Step-by-step explanation:
The method used here would simply be hit and trial
Now the first two numbers would be 1 and 7. 17 multiplied by 4 would give 68. 6 and 8 would be the digits in 3rd row. Now 25 is added with 68 and this would give 93 the last two digits of the last row
1 7 x 4 = 6 8 + 2 5 = 9 3
Solution:
Given => 1 to 9 all digits need to be used and every box should contain different digit which means repetition of digits not allowed.
If you get such type of puzzles you need to apply and trial method.
So , let's see the answer
In first two boxes 1 and 7 will be filled which will get multiplied by 4 i.e. our third box.
17 x 4 = 68
68 will fill the fourth and fifth box.
68 + 25 = 93
And then in sixth and seventh box with 25 which has given result 93 which fills last two boxes.
And no digit got repeated even.
1 7
x 4
_____
= 6 8
+ 2 5
_____
= 9 3