fimd the area enclosed befween y = sin x and X - axis befween 0 and 4pie
Answers
Answered by
1
Area =∫
0
y
dy
=∫
0
π
sinxdx=−[cosx]
0
π
=2.
solution
0
y
dy
=∫
0
π
sinxdx=−[cosx]
0
π
=2.
solution
Attachments:
Answered by
0
Answer:
The graph of y=sinx can be drawn as shown in the diagram.
∴ Required area =Area OABO+Area BCDB
=∫0πsin x dx+∣∣∣∣∣∫π2πsin x dx∣∣∣∣∣
=[−cosx]0π+∣∣∣[−cosx]π2π∣∣∣
=[−cosπ+cos 0]+∣−cos 2π+cos π∣
=1+1+∣(−1−1)∣
=2+∣−2∣
=2+2=4 sq. units
Step-by-step explanation:
Hope it will help. If it help than mark me brainliest please.
Attachments:
Similar questions