the perimeter of an aluminium sheet is 120 cm. If its length is reduced by 10% and its breadth is increased by 20% , the perimeter doesn't change. find the measures of length and breadth of the sheet.
the answer is l=40 and b=20
I want explanation
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P = 2(l+b)= 120
l+b= 120/2=60
ATQ
L-10+B+20
2(L-10%of L+B+20%of B)=2(L+B)
on solving this above eqn. u can get the answer.
L=40cm B=20cm.
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