Question

Fimd the sum of all three digits number s, which are divisible by 5​

Answer 1

Answer:

....................................................

Answer 2

Answer:

THE ANSWER IS 97455

Step-by-step explanation:

We need to find the sum of all three digit numbers which are divisible by 5.

AP: 100 , 105 , 110 , 115 , 120 , ............... , 995

HERE

First term (a) = 100

Common Difference (d) = 5

Last term (l) = 995

l = a + (n-1) d

=> 995 = 100 + (n-1)5

=> 995 - 100 = (n-1)5

=> 885/ 5 = n-1

=> 177 = n-1

=> n = 178

Sn = n/2 ( a + l )

= 178/2 (100 + 995)

= 89 × 1095

= 97455

so the answer is 97455

THANK YOU