Question

fimd three consecutive natural number, whose sum is 96

Answer 1

x,x+1 and x+2=96
3x+3=96
3x=93
x=31
then x+1=32
x+2=33

Answer 2

let the first no. be n
therefore, n + n+1 + n+2= 96
3n + 3 = 96
3n = 96-3
3n = 93
n = 93/3
n = 31

therefore, three consecutive numbers are
n=31 , n+1=31+1=32 , n+2=31+2=33