Fimd value if x-1 is factor of p(x)= k(x)^2-√2x+1
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i think _/2 + 1 is the correct value of K
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x-1is the factor
so x=1
p(x)=0.......x is the factor....(1)
p(x)=k(x)^2-root2x+1
p(1)=k(1)^2-root2×1+1
p(1)=k-root2+1
p(1)=k-1.414+1....root2 =1.414
0=k-0.414....from1
k=-0.414
hope it will help you
pradnya102:
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