Question

Fimd value if x-1 is factor of p(x)= k(x)^2-√2x+1

Answer 1

i think _/2 + 1 is the correct value of K

Answer 2

x-1is the factor

so x=1

p(x)=0.......x is the factor....(1)

p(x)=k(x)^2-root2x+1

p(1)=k(1)^2-root2×1+1

p(1)=k-root2+1

p(1)=k-1.414+1....root2 =1.414

0=k-0.414....from1

k=-0.414

hope it will help you