Question

find 1+3+5+.......+41​

Answer 1

Answer:

32 is the answer

Step-by-step explanation:

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Answer 2

Answer:

441

Step-by-step explanation:

It is a question of Arithmetic Progression

Sum of numbers= n/2(2a+(n-1)d)

Here,

a=1

d=3-1=2

And n can be found out with the help of

L= a+(n-1)d

41=1+(n-1)×2

So from here

n=21

Sum of odd numbers = n^2

So sum is 21^2

441

or

Putting the value in above equation

sum=21/2(2+(21-1)×2)

So sum would be 441