Find 1.4.7 + 3.6.9 + 5.8.11 + 7.10.13 +.... upto n terms
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Hey dear,
● Answer-
Sn = 2n^4 + 12n^3 + 17n^2 - 17n
● Explaination-
nth term in given series is given by-
tn = (2n-1)(2n+2)(2n+5)
tn = 8n^3 + 24n^2 + 6n - 10
To calculate sum of the series-
Sn = ∑ (8n^3 + 24n^2 + 6n - 10)
Sn = 8∑n^3 + 24∑n^2 + 6∑n - 10∑1
Sn = 8(n^2+n)^2/4 + 24n(n+1)(2n+1)/6 + 6n(n+1)/2 + 10n
Sn = 2n^4 + 12n^3 + 17n^2 - 17n
Therefore, sum upto n terms is 2n^4 + 12n^3 + 17n^2 - 17n .
Hope this help..
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