Question

Find
1) A:B:C
2) A:C


If 3A=4B=6C..



plzz no unecessary answers it is urgent....​

Answer 1

Given:

3A = 4B = 6C.

To Find:

(i) A:B:C

(ii) A:C

Concept Used:

We will take as 3A = 4B = 6C = k .

Here k is a constant.

Answer:

Here given that 3A = 4B = 6C

Let us admit 3A = 4B = 6C = k .

Now ,

$\sf{\implies3A = k .}$

$\sf{\leadsto A=\dfrac{k}{3}}$

Similarly ,

$\sf{\implies4B= k .}$

$\sf{\leadsto B=\dfrac{k}{4}}$

And ,

$\sf{\implies 6C = k .}$

$\sf{\leadsto A=\dfrac{k}{6}}$

$\rule{200}1$

Now ,

(i) A:B:C

= $\sf{\dfrac{k}{3}:\dfrac{k}{4}:\dfrac{k}{6}}$

=$\sf{ \dfrac{1}{3}:\dfrac{1}{4}:\dfrac{1}{6}}$

=$\sf{\dfrac{1}{3}\times12:\dfrac{1}{4}\times12:\dfrac{1}{6}\times12}$

$\red{\sf{\leadsto 4:3:2}}$

$\rule{200}1$

(ii) A:C

=$\sf{\dfrac{k}{3}:\dfrac{k}{6}}$

=$\sf{\dfrac{1}{3}:\dfrac{1}{6}}$

=$\sf{\dfrac{1}{3}\times6:\dfrac{1}{6}\times12}$

$\red{\sf{\leadsto 2:1}}$