find 1 and 2 plz it's urgent
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1) If AB=BC=4 cm and b is right angled,
So either AB is perpendicular or BC,
If you take AB as base,then Bc would be perpendicular and vice versa,
Applying formula for area of triangle,
(1/2) *base*perpendicular,
It is (1/2)*4*4=8cm^2
Hope u understood, feel free to ask if u have doubts.
2) The area of an equilateral triangle of side a = [(a^2)/2]sin 60 or
4*3^0.5 = [(a^2)/2]*3^0.5/2, or
2*2*4*3^0.5 = a^2 *3^0.5 or
a = 4 cm.
Hence the side of the equilateral triangle = 4 cm.
So either AB is perpendicular or BC,
If you take AB as base,then Bc would be perpendicular and vice versa,
Applying formula for area of triangle,
(1/2) *base*perpendicular,
It is (1/2)*4*4=8cm^2
Hope u understood, feel free to ask if u have doubts.
2) The area of an equilateral triangle of side a = [(a^2)/2]sin 60 or
4*3^0.5 = [(a^2)/2]*3^0.5/2, or
2*2*4*3^0.5 = a^2 *3^0.5 or
a = 4 cm.
Hence the side of the equilateral triangle = 4 cm.
jotdhillon57:
plz mera ek topic karoge
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