Question

Find 10th term in which A.p 3,8,13,17, ..... ,42

Answer 1

Answer:

48

Step-by-step explanation:

Given :

a = first term of the A.P = 3

d = common difference of the A.P = 8-3 =5

To find :

n = 10th term of the A.P

Nth term of and A.P is given by the formula nth term = a+(n-1)d

So Substituting the values :

10th term = 3+(10-1) 5

10th term = 3+9(5)

10 th term = 3+45

10th term = 48

The 10th term of the given Arithmetic progression is equal to 48

More :

• Sum of n terms of an A.P = n/2(a+l) or n/2 (2a+(n-1)d)

• Arithmetic progression also is similarly having types as geometric progression and harmonic progression

Answer 2

$\huge\sf\pink{Answer}$

☞ 10th term of the given AP is 48

$\rule{110}1$

$\huge\sf\blue{Given}$

✭ AP - 3,8,13,17......42

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$\huge\sf\gray{To \:Find}$

◈ Its 10th term?

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$\huge\sf\purple{Steps}$

In the given AP,

◕ a(First Trem) = 3

◕ d(Common Difference) = $\sf a_2 - a_1 = 5$

So now we know that,

$\underline{\boxed{\sf a_n = a+(n-1)d}}$

Substituting the given values,

➝ $\sf a_{10} = 3+(10-1)5$

➝ $\sf a_{10} = 3+(9)(5)$

➝ $\sf a_{10} = 3+45$

➝ $\sf\orange{a_{10} = 48}$

$\rule{170}3$