find 10th term of -1/2 , 1/2 , 3/2.....
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Answered by
1
As we know the formula ,
t = a+ (n-1)d.
Here,
a = -1/2
d = 1
n = 10
So, t10 = -1/2 +(10-1)1 = -1/2 + 9 = 17/2.
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t = a+ (n-1)d.
Here,
a = -1/2
d = 1
n = 10
So, t10 = -1/2 +(10-1)1 = -1/2 + 9 = 17/2.
Hope you will find it helpful....
Mark it as brainliest.
Answered by
1
Here -1/2,1/2, 3/2 form a A.P [ Arithmetic progression ].
We know that n th term = a+ (n – 1) d.
Common difference = d = 3/2-1/2=1
First term = -1/2
Hence, 10 th term
= -1/2+ (10-1)*1
=-1/2+9
=17/2.
The 10 th term of -1/2 , 1/2 , 3/2..... is 17/2
We know that n th term = a+ (n – 1) d.
Common difference = d = 3/2-1/2=1
First term = -1/2
Hence, 10 th term
= -1/2+ (10-1)*1
=-1/2+9
=17/2.
The 10 th term of -1/2 , 1/2 , 3/2..... is 17/2
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