Question

Find 11th term of the AP - 3,1/2,2,............................?​

Answer 1

Answer:

-22

Step-by-step explanation:

a = 3

d = 2nd term - 1st term = (1/2)-3 = -2.5

n = 11

an = a + (n-1)d

a of 11th term =a + (n-1)d

11th term of AP is = 3+(11-1)-2.5

= 3+(10)-2.5

=3+-25

=-22

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Answer 2

Answer: 22

To find:

The 11th term of the given A.P. $-3,\frac{1}{2},2,...$

Solution:

We know that the nth term of A.P. is given as,

$a_{n} = a+(n-1)d$

where,

a is first term

d is the common difference

n is the term.

So, in the given A.P.,

a= -3

$d =n_2-n_1\\=-\frac{1}{2} -(-3)\\=\frac{5}{2}$

n = 11

Substituting all the values in the formula,

$a_1_1=-3+(11-1)\frac{5}{2}\\ a_1_1=-3+10*\frac{5}{2}\\ a_1_=-3+25\\a_1_1=22$

Therefore, the 11th term of the A.P. is 22.