Question

The average degree of freedom per molecule for a gas is 6. The gas performs 25 ) of work when it expands at constant pressure. The
heat absorbed by the gas is​

Answer 1

According to question

Degree of freedom n = 6

Also Work Done = W = 25J

So

At constant pressure

heat absorbed

H = n * W

= 6 * 25

= 150 J

Thus answer is 3 ) 150 J

Answer 2

Answer:

100J

Explanation:

We know that, change in internal energy ΔU=nCv

ΔT= f/2 ×nRΔT

Where, f=no.of degrees of freedom=6

Also, work done at constant pressure, ΔW=nRΔT=25J

Heat absorbed=ΔQ=ΔU+ΔW

=4nRΔT=4×25J

=100J

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