Find 15th term of the series 3, -6, 12, -24,.............................
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Given ,
The GP is 3 , -6 , 12 , -24 , ...
- First term (a) = 3
- Common ratio (r) = -2
We know that , the first n terms of an GP is given by
Thus ,
15th term = 3 × (-2)^{15 - 1}
15th term = 3 × (-2)^{14}
15th term = 3 × 16384
15th term = 49152
Therefore , the 15th term of given series is 49152
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