Math, asked by ponnurk10, 6 months ago

Find 15th term of the series 3, -6, 12, -24,.............................​

Answers

Answered by Anonymous
2

Given ,

The GP is 3 , -6 , 12 , -24 , ...

  • First term (a) = 3
  • Common ratio (r) = -2

We know that , the first n terms of an GP is given by

  \boxed{ \tt{ a_{n} = a {r}^{(n - 1)} }}

Thus ,

15th term = 3 × (-2)^{15 - 1}

15th term = 3 × (-2)^{14}

15th term = 3 × 16384

15th term = 49152

Therefore , the 15th term of given series is 49152

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