find 16 th term of an A.P. , if sum of its fifth and sixth term is 14 and the sum of the eleven and fourteenth term is 56.
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Step-by-step explanation:
Let the first term is a and common difference is d
Let the first term is a and common difference is da14=a+(14−1)d=a+13d
Let the first term is a and common difference is da14=a+(14−1)d=a+13da8=a+(8−1)d=a+7d
Let the first term is a and common difference is da14=a+(14−1)d=a+13da8=a+(8−1)d=a+7da6=a+(6−1)d=a+5d
Put value a=−d in equation (2) we get
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