Question

FIND......................

Answer 1

According to the question, the deflected beam is in the shape of the parabola

x² = 4ay

and (0,0) is the point of maximum deflection.As deflection in the center is 9cm, y co-ordinate of the points of support is +9. Assuming the beam is symmetrically loaded and geometrically symetric about its center, x co-ordinates of the support points are -6 and 6.Hence (-6,9) and (6,9) lie on the beam and satisfy the given parabola.

So, 6² = 4a*9

or 36 = 36a

or a = 1

Thus the equation becomes

x² = 4y ...........(1)

Now deflection of the required points is 5cm. Therefore their y co-ordinate is 9-5 = 4

Putting this value of y in equation (1),we get

x² = 4*4

or x = ±4

Therefore (-4,4) , (4,4) are the points on the beam with deflection 5 cm.

Answer 2

Answer:

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