Question

find 1st 3 terms in the expansion of (8-5x) whole power
2/3​

Answer 1

Answer:

I hope this can help you

Step-by-step explanation:

Using binomial theorem, the 6th term of (a+b)

8

is 56a

3

b

5

Now substituting the given terms, we get

56⋅

(x

8/3

)

3

1

⋅x

10

⋅(logx)

5

=5600

56⋅

x

8

1

⋅x

10

⋅(logx)

5

=5600

x

2

(logx)

5

=100

x

2

(logx)

5

=10

2

x

5

2

.5

(logx)

5

=10

2

(x

5

2

logx)

5

=10

2

x

5

2

logx=10

5

2

logx

x

5

2

=10

5

2

x

x

5

2

=10

10

5

2

Comparing the both side, we get

x=10