Question

Find 2∫0(x2+e2x+1)dx as the limit of a sum

Answer 1

Answer:0

Step-by-step explanation:

This question is related to integration, so in this question no upper limit or lower limit is given hence it is a general integration type question which is as follows;

=2∫0(x2+e2x+1)dx

dx is given here it means the integration has to done with respect of 'x'

Step-1, multipling zero with the entire equation then get

= 2∫(0)dx

=2(0) (because integration of zero is

zero)

=0

So the answer of this 2∫0(x2+e2x+1)dx is 'zero'