Math, asked by ojaswi8384, 11 months ago

Find 2 consecutive numbers such that 3/4 of the larger numbers exceeds 1/2 of the smaller number by 5.

Answers

Answered by Anonymous
0

Answer:


Step-by-step explanation:

let n and n + 1 be two consecutive numbers such that


(3/4)(n + 1) = n/2 + 5

(3*n + 3)*2 = 4*(n + 10)

6*n + 6 = 4*n + 40

2*n = 34

n = 34/2 = 17

n + 1 = 18

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