find 2 consecutive odd natural number s ,the sum of whose squers is 394
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let the first no. be X
then the second no. will be (X+1)
According to question.
X² + (X+2)² = 394.
X² + X²+4X+4 = 394. (a+b)²=a²+2ab+b²
2X²+4X = 390.
2(X²+2X) = 390.
X²+2X = 390/2
X(X+2) = 195.
X+2 = 195/X.
then the second no. will be (X+1)
According to question.
X² + (X+2)² = 394.
X² + X²+4X+4 = 394. (a+b)²=a²+2ab+b²
2X²+4X = 390.
2(X²+2X) = 390.
X²+2X = 390/2
X(X+2) = 195.
X+2 = 195/X.
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