solve x 2 -2ax-(4b 2 -a 2 )=0
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x2 -2ax-(4b 2- a 2)=0
x^2 -2ax -[(2b)^2-a^2]=0
x^2-(2b+a)x+(2b-a)x-(2b+a)(2b-a)=0
x[x-(2b+a)]+(2b-a)[x-(2b+a)]=0
[x-(2b+a)][x+(2b-a)]=0
therefore
x-(2b+a)=0 or x+(2b-a)=0
x=2b+a or x= a-2b
x^2 -2ax -[(2b)^2-a^2]=0
x^2-(2b+a)x+(2b-a)x-(2b+a)(2b-a)=0
x[x-(2b+a)]+(2b-a)[x-(2b+a)]=0
[x-(2b+a)][x+(2b-a)]=0
therefore
x-(2b+a)=0 or x+(2b-a)=0
x=2b+a or x= a-2b
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