Find 2 consecutive odd positive integers, sum of whose squares is 290
Answers
Answered by
1
Answer:
11,13
Step-by-step explanation:
11*11=121
13*13= 169
121+169=290
Answered by
1
Answer:
let two consecutive odd positive integers be x and x+2.
A.T.Q -
x^2 + (x+2)^2 = 290
Similar questions