find 27x^3 +8y^3 if 3x+2y =14 and xy =8
Answers
Answered by
115
3x+2y = 14
cube on both sides,
(3x+2y)^3 =14^3
27x^3 +8y^3 +3(3x*2y)[3x+2y] = 2744
27x^3 +8y^3 +[3*(6)(xy)(14)] = 2744
27x^3 +8y^3 + [18*14*8] = 2744
27x^3 +8y^3 = 2744 - 2016
27x^3 +8y^3 = 728
i hope this will help you
- by ABHAY
cube on both sides,
(3x+2y)^3 =14^3
27x^3 +8y^3 +3(3x*2y)[3x+2y] = 2744
27x^3 +8y^3 +[3*(6)(xy)(14)] = 2744
27x^3 +8y^3 + [18*14*8] = 2744
27x^3 +8y^3 = 2744 - 2016
27x^3 +8y^3 = 728
i hope this will help you
- by ABHAY
Answered by
20
3x+2y = 14
cube on both sides,
(3x+2y)^3 =14^3
27x^3 +8y^3 +3(3x*2y)[3x+2y] = 2744
27x^3 +8y^3 +[3*(6)(xy)(14)] = 2744
27x^3 +8y^3 + [18*14*8] = 2744
27x^3 +8y^3 = 2744 - 2016
27x^3 +8y^3 = 728
pls mark me as brainliest
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