Question

Find 3 consecutive integers such that the third is one and a half times the first.

Answer 1

Let the three consecutive integers be x - 1, x, x + 1.

Given that Third is one and a half times the first.

= > (x + 1) = 1 1/2(x - 1)

= > (x + 1) = (3/2) (x - 1)

= > (x + 1) = 3(x - 1)/2

= > 2(x + 1) = 3(x - 1)

= > 2x + 2 = 3x - 3

= > 2x = 3x - 5

= > x = 5.


Now,

x - 1 = 5 - 1 = 4

x + 1 = 5 + 1 = 6.


Therefore, the three consecutive integers are 4,5,6.