Find 3 consecutive natural numbers such that the sum of the first and second is 15 more than the third
Answers
Answered by
2
Let numbers are x, ( x + 1 ), ( x + 2 )
According to the question,
=> x + x + 1 = 15 + x + 2
=> 2x - x = 15 + 2 - 1
=> x = 16
Hence, Numbers are 16, 17, 18
According to the question,
=> x + x + 1 = 15 + x + 2
=> 2x - x = 15 + 2 - 1
=> x = 16
Hence, Numbers are 16, 17, 18
Answered by
5
Let numbers are x, ( x + 1 ), ( x + 2 )
According to the question,
=> x + x + 1 = 15 + x + 2
=> 2x - x = 15 + 2 - 1
=> x = 16
Hence, Numbers are 16, 17, 18
According to the question,
=> x + x + 1 = 15 + x + 2
=> 2x - x = 15 + 2 - 1
=> x = 16
Hence, Numbers are 16, 17, 18
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