Question

Find 3 consecutive no.whose sum is 108

Answer 1

heya!!!

let the ist no. be x

second consecutive no. is x + 1

3rd consecutive no. is x + 2


According to the question.


x + x +1 + x + 2 = 180

3x = 177

x = 59

so, the three consecutive no.s are 59, 60 and 61


Have a great future ahead

Answer 2

Answer:

Step-by-step explanation:

Let the first number be X - 1 ..... (1)

Let the second number be X .....(2)

Let the third number be X + 1 ......(3)

According to the question :-

The sum of all three numbers = 108

(X-1) + (X) + (X+1) =108

X-1+X+X+1 = 108

3X + 0 = 108

3X = 108

X = 108/3

X. = 36

BY SUBSTITUTING THIS VALUE OF X WHICH IS 36, in equations 1,2 and 3

We get,

X -1 = 36

x = 36 and

X + 1 = 37