Question

find 3 consecutive odd no.whose sum is 147

Answer 1

Hi Friend !!!

Here is ur answer !!!

Let the number be 2x+1 , 2x+3 and 2x+5

2x+1+2x+3+2x+5 = 147

6x + 9 = 147

3(2x+3 ) = 147

2x+3 = 147/3

2x = 49-3

2x = 46

x = 46/2

x = 23

So, the numbers are

2x+1 = 2(23)+1

= 46+1

= 47

2x+3 = 2(23)+3

= 46+3

= 49

2x+5 = 2(23)+5

= 46+5

= 51

Hope it helps u : )

Answer 2

hii. .....friend

the answer is here,

Let the three consecutive odd no. s be
2x+1 , 2x+3 & 2x+ 5.

Fro the question,

=> 2x+1+2x+3+2x+5 =147.

=> 6x+9 =147.

=> 6x= 138.

=> x= 23.

So, The numbers are

=> 2(23)+1 => 47.

=> 2 (23)+3 => 49.

=> 2 (23)+5 => 51.


:-)Hope it helps u.