find 3 consecutive term which are in AP.whose sum is 24 & product is 440
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x-y, x, x+y
x-y+ x + x+y = 24
3x = 24
x = 8
(x-y(x+y)x = 440
(x² - y² )x = 440
x³ - xy² = 440
512 - 8y² = 440
y² = 9
y = 3
So numbers 8-3 = 5, 8, 8+3=11
5, 8, 11
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