Question

Find 3 consecutive terms in ap whose sum is 18 and sum of its square is 140

Answer 1

Answer: 6-√6, 6 and 6+√6

Step-by-step explanation:

Let m be the middle term of these three and d be the common difference.

Then the numbers are m-d, m and m+d

Sum=18

3m=18

m=6

product =180

(m-d)m(m+d)=180

(6-d)6(6+d)=180

6(36-d²)=180

6d² =6x36-180 = 36

d² = 6

d=√6

So the terms are 6-√6, 6 and 6+√6