Question

find 3 different solution of equation 4x+3y=12​

Answer 1

Answer:

ATQ,

4x+3y=12

4x=12-3y

x=12-3y÷4

x=3-3y-ans

ATQ,

4x+3y=12

3y=12-3x

y=12-3x÷3

y=4-3x-ans

ATQ,

4x+3y=12

xy(4+3)=12

xy×7=12

xy=12÷7-ans

Answer 2

Answer:

( 0, 4 ), ( 3, 0 ) and ( 1, 8/3 ) are three of the solutions.

Step-by-step explanation:

The given equation is a linear equation in two variables as the exponent of x and y are 1. And it can be rewritten in the form ax + by + c = 0, where x and y are variable.

A linear equation in two variable has infinite number of solutions. We can find any three. To find the solutions, we can assume x aur y as any constant value, which will make the equation a linear equation in one variable.

Given equation: 4x + 3y = 12

Let x = 0

⟹ 4(0) + 3y = 12

⟹ 0 + 3y = 12

⟹ y = 12/3

⟹ y = 4

First solution is ( 0, 4 )

Let y = 0

⟹ 4x + 3(0) = 12

⟹ 4x = 12

⟹ x = 12/4

⟹ x = 3

Second solution is ( 3, 0 )

Let x = 1

⟹ 4(1) + 3y = 12

⟹ 4 + 3y = 12

⟹ 3y = 12 - 4

⟹ 3y = 8

⟹ y = 8/3

Third solution is ( 1, 8/3 )