Question

find 3 numbers which are in AP whose sum and products are 24 & 480 respectively

Answer 1

let the three numbers be (a-d), a and (a+d),

then

a-d + a + a+d=24,


3a=24,

then

a=8,


also


(a-d)×a(a+d)=480,


(8-d)×8×(8+d)=480,


(8²-d²)×8=480,


64-d²=60,


then


64-60=d²,

d²=4,


d=2,


therefore

1st number=(8-2)=6,


2nd number=8,


3rd number=(8+2)=10