find the value of x sin2x=sin60cos30-cos60sin30
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Sin60°=√3/2
Cis30°=√3)2
Sin30°=1/2
Cos60°=1/2
Sib60°Cos30°-Cis60°Sin30°
√3/2×√3/2 - 1/2×1/2
3/4 -1/4
By taking LCM
3-1/4=2/4
=1/2
Sin2x=Sin60°
x=60/2
x=30°
Cis30°=√3)2
Sin30°=1/2
Cos60°=1/2
Sib60°Cos30°-Cis60°Sin30°
√3/2×√3/2 - 1/2×1/2
3/4 -1/4
By taking LCM
3-1/4=2/4
=1/2
Sin2x=Sin60°
x=60/2
x=30°
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answer yeh nhi hai per like keedo bhai
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