Question

find 3x^2 +48x +117 using identities. pls help me​

Answer 1

Answer:

divide this equation with 3

we get

$x {}^{2} + 16x + 39 \\ = x {}^{2} + 13x + 3x + 39 \\ = x(x + 13) + 3(x + 13) \\ = (x + 13)(x + 3)$

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Answer 2

Answer:

Given:             3x² +48x +117

⇒             3x² + 39x + 9x + 117

⇒           3x ( x + 13) + 9 ( x + 13)

⇒               (3x + 9)(x + 13)

now,

Case 1,                                                

         3x + 9 = 0                              

⇒          3x = - 9

∴             x = - 3

Case 2,

        x + 13 = 0

∴         x = - 13

∴  So there will be two values of x = - 13 and -3

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