Question

find 4/5 of 5/12 of a chocolate​

Answer 1

Answer:

LCM of

$\frac{4}{5}$

and

$\frac{5}{12}$

is 60

so multilpy

$\frac{4}{5} \times 12 = \frac{48}{60}$

and

$\frac{5}{12 } \times 5 = \frac{25}{60}$

now substrate

$\frac{48}{60} - \frac{25}{60 } = \frac{23}{60}$

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