find 4 arithmetic means between 1/9 and 9
Answers
Answered by
0
Answer:
Fourth arithmetic mean is 3
Step-by-step explanation:
Let A_1,A_2 ,A_3 ,A_4 , A_5, A_6A
1
,A
2
,A
3
,A
4
,A
5
,A
6
be 6 six arithmetic between 1 and 9/2
Let d be the common difference.
\begin{gathered}A_1=1+d\\\\A_2=1+2d\\\\A_3=1+3d\\\\A_4=1+4d\\\\A_5=1+5d\\\\A_6=1+6d\\\\\frac{9}{2}=1+7d\\\\\frac{9}{2}-1=7d\\\\\frac{9-2}{2}=7d\\\\\frac{7}{2}=7d\\\\d=\frac{1}{2}\end{gathered}
A
1
=1+d
A
2
=1+2d
A
3
=1+3d
A
4
=1+4d
A
5
=1+5d
A
6
=1+6d
2
9
=1+7d
2
9
−1=7d
2
9−2
=7d
2
7
=7d
d=
2
1
Now,
Fourth arithmetic mean
\begin{gathered}=A_4\\\\=1+4d\\\\=1+4(\frac{1}{2})\\\\=1+2\\\\=3\end{gathered}
=A
4
=1+4d
=1+4(
2
1
)
=1+2
=3
Similar questions